lavos/cap3/ex15.go

package cap3

var (
    cashes = []int{50, 20, 10, 5, 2, 1}
)

// Ex15 最少的纸币找零钱
func Ex15(amount, paid int) map[int]int {
    result := map[int]int{}

    // 还要找的钱
    change := paid - amount
    for i, cash := range cashes {
        // 当前面额需要找的张数，整除后结果为0说明当前面额不足以找零
        cashNum := change / cash
        if cashNum != 0 {
            result[i] = cashNum
            // 当前面额找完后更新剩余未找余额
            change = change - cashNum*cash
        }
    }

    return result
}