package cap3

var (
	cashes = []int{50, 20, 10, 5, 2, 1}
)

// Ex15 最少的纸币找零钱
func Ex15(amount, paid int) map[int]int {
	result := map[int]int{}

	// 还要找的钱
	change := paid - amount
	for i, cash := range cashes {
		// 当前面额需要找的张数，整除后结果为0说明当前面额不足以找零
		cashNum := change / cash
		if cashNum != 0 {
			result[i] = cashNum
			// 当前面额找完后更新剩余未找余额
			change = change - cashNum*cash
		}
	}

	return result
}